Bis(p-methoxyphenyl) Telluride

The title compound, C₁₄H₁₄O₂Te, displays an angular geometry at tellurium, with a C-Te-C angle of 99.5 (1)° and Te-C distances of 2.110 (3) and 2.112 (3) Å. The Te atom is displaced by 0.1963 (3) and 0.0044 (3) Å out of the planes of the aromatic rings. These rings are approximately perpendicular to one another [dihedral angle 70.4 (1)°], while each methoxy group is almost coplanar with the phenyl ring to which it is bonded [dihedral angles 3.3 (2) and 1.5 (3)°].

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