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In the title mol­ecule, C13H13FN2OS, the heterocyclic ring adopts a slightly distorted flattened boat conformation, and the plane through the four coplanar atoms makes a dihedral angle of 87.45 (14)° with the benzene ring. The thione, acetyl and methyl groups lie on the opposite side of the heterocyclic mean plane to the fluorophenyl group, which has an axial orientation. N—H...O, N—H...S, C—H...F and C—H...O inter­molecular hydrogen bonds and a weak C—H...π inter­action involving the benzene ring are found in the crystal structure.

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In the title mol­ecule, C16H20N2OS, the heterocyclic ring adopts a slightly distorted flattened boat conformation, and the plane through the four coplanar atoms makes a dihedral angle of 86.98 (6)° with the benzene ring. The thione, acetyl and methyl groups lie on the opposite side of the heterocyclic mean plane to the isopropylphenyl group which has an axial orientation. A weak intra­molecular C—H...O hydrogen bond is observed. In the crystal, molecules are linked via N—H...O, N—H...S and C—H...S hydrogen bonds.

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In the title mol­ecule, C19H13FN2, the benzimidazole unit is close to planar [maximum deviation = 0.0342 (9) Å] and forms dihedral angles of 58.94 (3) and 51.43 (3)° with the phenyl and fluoro­benzene rings, respectively; the dihedral angle between the phenyl and fluoro­benzene rings is 60.17 (6)°. In the crystal, three C—H...F hydrogen bonds and two weak C—H...π inter­actions involving the fused benzene ring lead to a three-dimensional architecture.
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