metal-organic compounds
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In the title compound, [Re2(CH3O)2(CO)6(C4H6N3O)], the two ReI atoms are linked by a methoxo and methanolato bridge, as well as by a creatinine ligand that coordinates in a bidentate fashion. Three fac-carbonyl ligands occupy the rest of the slightly distorted octahedral geometry around each ReI atom. The bridging methanolato and methoxo ligands are bent out of the Re2O2 plane by 49.2 (4) and 47.8 (3)° respectively. This is normally associated with a methanolato-bridging-type coordination rather that the more planar methoxo-type bridging. Furthermore, the creatinine bridging molecule is very slightly distorted from the Re2N2C plane, indicating that the pyrazolo N atom bonded to the RhI atom is not protonated. Charge balance can thus only be attained if one assumes a positional disorder for the methanolato/methoxo H atom. All attempts to locate disordered protons around these O atoms were unsuccessful. Four hydrogen bonds, one N—HO and three C—HO, are observed in the structure. The molecules pack in a head-to-head and tail-to-tail fashion when viewed along the c axis, in alternating columns.
metal-organic compounds
Open access
In the title compound, [Cu(C11H11BrNO)2], the CuII atom is in a distorted square-planar geometry, with the two bidentate ketimine ligands positioned in a trans geometry. Two intermolecular C—HO hydrogen bond interactions are present which link the molecules in a zigzag manner along the a axis. The molecules pack in layers along the diagonal of the bc plane.
organic compounds
Open access
The title compound, C10H15NO2, crystallized with three molecules in the asymmetric unit. These three molecules are quite similar except for slight differences in the torsion angles of the substituents on the ring. The isopropyl C—C—N—C torsion angles (towards the carbon next to the ethyl bound carbon), for example, are −150.63 (11), −126.77 (13) and −138.76 (11)° for molecules A, B and C, respectively, and the C—C—C—N torsion angles involving the ethyl C atoms are 102.90 (13), 87.81 (14) and 86.47 (13)°. The main difference between the three molecules lies in the way they are arranged in the solid-state structure. All three molecules form dimers that are connected through strong O—HO hydrogen bonds with R22(10) graph-set motifs. The symmetry of the dimers formed does however differ between molecules. Molecules B connect with each other to form inversion dimers. Molecules A and C, on the other hand, form dimers with local twofold symmetry, but the two molecules are crystallographically distinct. The B and C molecules are linked to themselves and to each other via C—HO hydrogen bonds. This results in the formation of a three-dimensional network structure.