organic compounds
The title compound, C15H12NO2F3, adopts the phenol–imine tautomeric form. The two aromatic rings are twisted with respect to each other, with a dihedral angle of 17.83 (19)°. O—HN and O—HF intramolecular interactions are found in the molecule, and the solid-state structure is stabilized by intermolecular C—HO and C—HF hydrogen bonds, to form a two-dimensional network.
organic compounds
The molecule of the title compound, C14H13NO3, adopts the keto–amine tautomeric form. An intramolecular N—HO hydrogen bond dictates the essentially planar molecular geometry; the two benzene rings make a dihedral angle of 7.93 (7)°. The crystal packing is stabilized by intermolecular O—HO and C—HO hydrogen bonds.
organic compounds
The title compound, C19H23N3O4, adopts the keto-amine tautomeric form, with the H atom located on N rather than on O. This H atom is involved in a strong intramolecular hydrogen bond. The configuration around the azo N=N double bond is trans and the dihedral angle between the two aromatic rings is 8.94 (2)°. The molecules, with intramolecular N—HO hydrogen bonding, are linked by intermolecular O—HO hydrogen bonds, forming a three-dimensional network.
organic compounds
The title compound, C20H25N3O5, adopts the keto–amine tautomeric form and displays the characteristic features of azobenzene derivatives. Intramolecular N—HO and O—HO and intermolecular O—HO interactions influence the conformation of the molecules and the crystal packing.
organic compounds
The molecule of the title compound, C13H9ClN2O2, is approximately planar and displays a trans configuration with respect to the central N=N double bond. The dihedral angle between the two aromatic rings is 3.69 (14)°. The molecules are linked by intermolecular O—HO hydrogen bonds, forming a two-dimensional network.
organic compounds
The molecule of the title compound, C13H9BrN2O2, is approximately planar and displays a trans configuration with respect to the N=N double bond. The dihedral angle between the two aromatic rings is 3.65 (16)°. The molecules are linked by intermolecular O—HO hydrogen bonds, forming a two-dimensional network.
organic compounds
The molecule of the title compound, C15H14N2O2, is approximately planar and displays a trans configuration with respect to the N=N double bond. The dihedral angle between the two aromatic rings is 10.90 (14)°. The molecules are stacked via weak C—Hπ interactions.
organic compounds
The title structure, C14H11BrN2O3, displays the characteristic features of azobenzene derivatives. The two aromatic rings are nearly coplanar, forming a dihedral angle of 8.71 (12)°. There is a strong intramolecular O—HO bond, and weak π–π and C—Hπ interactions stabilize the structure.
organic compounds
The title compound, C14H11FN2O3, displays the characteristic features of azobenzene derivatives. Intramolecular O—HO and weak π–π interactions influence the conformation of the molecules and the crystal packing. The azobenzene moiety of the molecule has a trans configuration and the dihedral angle between the planes of the two aromatic rings is 10.13 (8)°.