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In the title compound, C13H10BrNO, the benzene ring planes are inclined at an angle of 48.85 (17)°, resulting in a nonplanar mol­ecule. A characteristic of aromatic Schiff bases with N-aryl substituents is that the terminal phenyl rings are twisted relative to the HC=N plane. In this case, the HC=N unit makes dihedral angles of 11.1 (4) and 38.5 (3)° with the hy­droxy­benzene and bromo­benzene rings, respectively. In the crystal, the molecules are linked by O—H...N hydrogen bonds to form infinite (C8) chains along the b axis.

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In the title compound, C14H13NO, the two rings show significant deviation from coplanarity, with a dihedral angle between the two planes of 49.40 (5)°. The hy­droxy group is involved in an inter­molecular O—H...N hydrogen bond, forming an extended one-dimensional zigzag chain along (001).
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