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In the title compound, C16H21NO2, the indoline ring and the two ketone O atoms are approximately coplanar, the largest deviation from the mean plane being 0.063 (2) Å. The mean plane through the fused ring system is nearly perpendicular to the mean plane passing through the 1-octyl chain [dihedral angle = 77.53 (17)°]. In the crystal, molecules are linked by C—H
O hydrogen bonds, forming a three-dimensional network.
O hydrogen bonds, forming a three-dimensional network.organic compoundsOpen access
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The asymmetric unit of the title compound, C17H17N3O2S, contains two independent molecules linked by an N—HO hydrogen bond. The molecules show different conformations. In the first molecule, the fused five- and six-membered ring system is almost perpendicular to the plane through the atoms forming the allyl group, as indicated by the dihedral angle of 85.1 (4)°. The dihedral angle with the methylbenzenesulfonamide group is 78.8 (1)°. On the other hand, in the second molecule, the dihedral angles between the indazole plane and the allyl and methylbenzenesulfonamide groups are 80.3 (3) and 41.5 (1)°, respectively. In the crystal, molecules are further linked by N—HN and C—HO hydrogen bonds, forming a three-dimensional network.
O hydrogen bond. The molecules show different conformations. In the first molecule, the fused five- and six-membered ring system is almost perpendicular to the plane through the atoms forming the allyl group, as indicated by the dihedral angle of 85.1 (4)°. The dihedral angle with the methylbenzenesulfonamide group is 78.8 (1)°. On the other hand, in the second molecule, the dihedral angles between the indazole plane and the allyl and methylbenzenesulfonamide groups are 80.3 (3) and 41.5 (1)°, respectively. In the crystal, molecules are further linked by N—HN and C—HO hydrogen bonds, forming a three-dimensional network.
