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In the title compound, C31H28N2O, the dihedral angles formed by the imidazole ring with the three aryl substituents are 18.52 (8) and 85.56 (7) and 85.57 (7)°, respectively. In the crystal, mol­ecules are linked by O—H...N and C—H...O hydrogen bonds into chains parallel to the a axis.

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In the title compound, C30H25ClN2, the chiral center maintains the S configuration of the stating L-phenyl­alaninol. The two phenyl groups closest to the substituted N atom adopt an almost perpendicular orientation relative to the central imidazole ring, with dihedral angles of 88.9 (4) and 84.7 (3)°. The third phenyl group is nearly coplanar with it, making a dihedral angle of 11.0 (5)°.

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In the title compound, C29H25N3O, the central imidazole ring forms dihedral angles of 64.7 (3), 33.5 (3) and 81.2 (2)° with the pyridyl and two phenyl substituents, respectively. An intra­molecular C—H...N hydrogen bond is observed. In the crystal, O—H...N and C—H...O hydrogen bonds link the mol­ecules into chains parallel to the a axis.
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