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In the title mol­ecule, C15H9N3O2S, the central imidazo[2,1-b][1,3]benzo­thia­zole heterotricyclic unit is essentially planar (r.m.s. deviation = 0.021 Å). The terminal phenyl ring and nitro group are twisted by 9.06 (1) and 11.02 (4)°, respectively, from the mean plane of the heterotricycle. In the crystal, mol­ecules are linked by π–π stacking inter­actions into columns along [100]; the inter­planar distance between neighboring imidazo[2,1-b][1,3]benzo­thia­zole planes within the columns is 3.370 (2) Å. Furthermore, the columns interact with each other by secondary S...O [2.9922 (10) and 3.1988 (11) Å] inter­actions, forming a three-dimensional framework.

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In the title mol­ecule, C16H15BrN2S2, the central imidazo[2,1-b]thia­zole fragment is almost planar (r.m.s. deviation = 0.012 Å), and the fused 5,6,7,8-tetra­hydro­benzene ring adopts an unsymmetrical half-chair conformation. The dihedral angle between the imidazo[2,1-b]thia­zole and benzene planes is 18.25 (4)°. The terminal methyl­sulfanyl substituent lies practically within the benzene plane [the dihedral angle between the corresponding planes is 7.20 (10)°] and is turned toward the C—Br bond. In the crystal, mol­ecules form infinite chains along [100] via secondary Br...N inter­actions [3.1861 (16) Å]. The chains are arranged at van der Waals distances.

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The title compound, C15H14N2S, crystallizes with two independent mol­ecules in the asymmetric unit. The central imidazo[2,1-b][1,3]benzo­thia­zole unit is planar (r.m.s. deviations of 0.010 and 0.008 Å for the two independent mol­ecules). The fused tetra­hydro­hexane ring adopts a half-chair conformation. The phenyl substituent is twisted by 16.96 (13) and 22.89 (12)° relative to the central imidazo[2,1-b][1,3]benzo­thia­zole unit in the two mol­ecules. In the crystal, there are no significant intermolecular interactions present.
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