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In the title compound, C17H13NO, the azomethine double bond adopts an E conformation. The naphthyl ring system and the benzene ring form a dihedral angle of 8.09 (10)°. The near-planar conformation of the molecule is consolidated by an intramolecular O—H
N hydrogen bond, which forms an S(6) ring. In the crystal, molecules are arranged in a zigzag fashion parallel to the c axis.
N hydrogen bond, which forms an S(6) ring. In the crystal, molecules are arranged in a zigzag fashion parallel to the c axis.organic compoundsOpen access
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In the title compound, C19H20N2O6, the azomethine [C=N = 1.269 (2) Å] double bond adopts an E conformation and the dihedral angle between the planes of the benzene rings is 17.41 (11)°. In the crystal, inversion dimers linked by pairs of N—HO hydrogen bonds generate R22(16) loops. The dimers are connected by C—HO and C—HN hydrogen bonds, forming sheets lying parallel to (100).
O hydrogen bonds generate R22(16) loops. The dimers are connected by C—HO and C—HN hydrogen bonds, forming sheets lying parallel to (100). organic compoundsOpen access
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The asymmetric unit of the title compound, C7H11N3O5S, contains two independent molecules with virtually identical conformations. The imidazole rings of both molecules are essentially planar (r.m.s. deviations = 0.0019 and 0.0038 Å), with a dihedral angle 9.25 (19)° between them. The nitro groups are oriented at 4.5 (2) and 6.44 (13)° with respect to the imidazole rings. In the crystal, molecules are linked to form a three-dimensional framework by C—HO and C—HN hydrogen bonds.
O and C—HN hydrogen bonds.organic compoundsOpen access
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In the structure of the title compound, C13H8ClNS, the dihedral angle between the benzothiazole ring system and the phenyl ring is 7.11 (8)°. In the crystal, molecules are arranged parallel to the c axis.
