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There are two independent mol­ecules (A and B) in the asymmetric unit of the title compound C11H10BrClO2, which represents the Z isomer. The methyl­acrylate moieties are essentially planar, within 0.084 (2) and 0.027 (5) Å in mol­ecules A and B, respectively. The benzene ring makes dihedral angles of 13.17 (7) and 27.89 (9)° with the methyl­acrylate moiety in mol­ecules A and B, respectively. The methyl­bromide moiety is almost orthogonal to the benzene ring, making dihedral angles of 81.46 (16)° in mol­ecule A and 79.61 (16)° in mol­ecule B. The methyl­acrylate moiety exhibits an extended trans conformation in both mol­ecules. In the crystal, pairs of C—H...O hydrogen bonds result in the formation of quasi-centrosymmetric R22(14) AB dimers.

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There are two independent mol­ecules (A and B) in the asymmetric unit of the title compound, C14H12ClNO3. The mean planes of the methyl ester unit (Cmeth­yl—O—C=O; r.m.s. deviation = 0.051 Å for mol­ecule A and 0.016 Å for mol­ecule B) and the chloro­quilonine ring system (r.m.s. deviation = 0.023 Å for mol­ecule A and 0.014 Å for mol­ecule B) form dihedral angles of 63.5 (1)° in mol­ecule A and 78.1 (1)° in mol­ecule B. The main difference between the two independent mol­ecules is reflected in the (H)O—C—C=C(H2) torsion angle which is −109.7 (2)° in mol­ecule A and 10.6 (2)° in mol­ecule B. An intra­molecular O—H...O hydrogen bond is observed in mol­ecule A. In the crystal, mol­ecules A and B are linked into pairs via bifurcated O—H...(N,Cl) hydrogen bonds and a weak C—H...O hydrogen bond links pairs of mol­ecules into chains along [100].
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