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The title compound, C14H14N2O3, is the exo isomer with a syn arrangement of two O atoms in the isoxazole and oxazine rings. The dihedral angle between the isoxazole and phenyl rings is 60.38 (4)°. In the crystal, weak C—H
O hydrogen bonds link the molecules, forming a three-dimensional network. The isoxazole O atom is an acceptor for three of these hydrogen bonds.
O hydrogen bonds link the molecules, forming a three-dimensional network. The isoxazole O atom is an acceptor for three of these hydrogen bonds.organic compoundsOpen access
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The title compound, C15H17NO4, is the exo isomer with a syn arrangement of the O atom in the isoxazole ring to the methyl group of the bicyclic alkene. The dihedral angle between the isoxazole ring and the benzene ring is 7.42 (9)°. In the crystal, weak C—HO hydrogen bonds link molecules, forming a three-dimensional network. The isoxazole O atom is an acceptor for both weak hydrogen bonds.
O hydrogen bonds link molecules, forming a three-dimensional network. The isoxazole O atom is an acceptor for both weak hydrogen bonds.organic compoundsOpen access
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The stereochemistry and regioschemistry (exo) of the title compound, C15H18O5, were determined by the X-ray analysis. The methoxy groups essentially lie in the plane of the benzene ring to which they are attached, as described by the C—O—C![[pdbond]](/logos/entities/z-pdbond_rmgif.gif)
C torsion angles of −176.80 (12) and 4.67 (19)°. In the crystal, O—HO hydrogen bonds and weak C—HO hydrogen bonds link the molecules, forming chains of R21(8) rings along [010].
C torsion angles of −176.80 (12) and 4.67 (19)°. In the crystal, O—HO hydrogen bonds and weak C—HO hydrogen bonds link the molecules, forming chains of R21(8) rings along [010].
