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The title compound, C20H19BrO2S, was synthesized by the cyclization of 1-(4-bromo­phenyl)-4-(3,4-di­methoxy­phenyl)-2,3-di­methyl­butane-1,4-dione with 2,4-bis(4-methoxy­phenyl)-2,4-disulfanyl­ene-1,3,2,4-di­thia­diphosphetane. The dimethoxyphenyl and bromophenyl rings make dihedral angles of 28.4 (3) and 45.0 (3)°, respectively, with the thiophene ring. The bond lengths are unexceptional.

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The molecule of the title compound, C15H14N2O3, is non-planar. The asymmetric unit contains two independent mol­ecules which are quite distinct from each other. Two bifurcated inter­molecular N—H...O hydrogen bonds help to establish the mol­ecular conformation and consolidate the crystal packing.

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The title compound, C21H19N3O3, was prepared by the reaction of 4-benz­yloxy-3-methoxy­benzaldehyde and isonicotinohydrazide. The vanillin group makes dihedral angles of 27.88 (7) and 58.94 (6)° with the planes of the pyridine and phenyl rings, respectively. A weak inter­molecular C—H...N hydrogen bond helps to consolidate the crystal packing.

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The molecule of the title compound, C14H13N3O3, is non-planar. The iso­vanillin group is almost perpendicular to the pyridine ring, the dihedral angle being 85.26 (7)°. An inter­molecular N—H...O hydrogen bond and a bifurcated intra/inter­molecular O—H...O,N hydrogen-bond system help to establish the mol­ecular conformation and consolidate the crystal packing.

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The title compound, C20H16N4O5, is non-planar. The central benzene ring makes dihedral angles of 58.14 (6) and 5.00 (9)° with the terminal phenyl ring and the nitro­phenyl­hydrazine mean plane, respectively. A bifurcated intra/inter­molecular N—H...(O,O) hydrogen bond helps to establish the mol­ecular conformation and consolidate the crystal packing.

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The molecule of the title compound, C20H18N4O6·C3H3N, is non-planar. The central benzene ring makes dihedral angles of 85.73 (10) and 2.70 (12)° with the terminal phenyl ring and the nitro­phenyl­hydrazine mean plane, respectively. An intra­molecular N—H...O hydrogen bond helps to establish the mol­ecular conformation.

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The title compound, C27H27N3O3, was prepared by the reaction of 4-(benz­yloxy)-3-ethoxy­benzaldehyde and 4-amino-1,5-dimethyl-2-phenyl-1H-pyrazol-3(2H)-one. The ethyl­vanillin group makes dihedral angles of 72.97 (8) and 76.75 (5)° with the planes of the two terminal phenyl rings, and an angle of 39.24 (5)° with the pyrazolone ring plane. Inter­molecular C—H...N and C—H...O hydrogen bonds help to consolidate the crystal packing.

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The molecule of the title compound, C17H19N3O4, is not planar. The isovanillin group makes a dihedral angle of 3.23 (14)° with the phenyl­hydrazine residue. The nitro group and its attached aromatic ring are not coplanar, the dihedral angle between them being 3.18 (6)°. Inter­molecular N—H...O and C—H...O hydrogen bonds link adjacent mol­ecules, forming infinite chains.
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