organic compounds
The title compound, C20H19BrO2S, was synthesized by the cyclization of 1-(4-bromophenyl)-4-(3,4-dimethoxyphenyl)-2,3-dimethylbutane-1,4-dione with 2,4-bis(4-methoxyphenyl)-2,4-disulfanylene-1,3,2,4-dithiadiphosphetane. The dimethoxyphenyl and bromophenyl rings make dihedral angles of 28.4 (3) and 45.0 (3)°, respectively, with the thiophene ring. The bond lengths are unexceptional.
organic compounds
The molecule of the title compound, C15H14N2O3, is non-planar. The asymmetric unit contains two independent molecules which are quite distinct from each other. Two bifurcated intermolecular N—HO hydrogen bonds help to establish the molecular conformation and consolidate the crystal packing.
organic compounds
The title compound, C21H19N3O3, was prepared by the reaction of 4-benzyloxy-3-methoxybenzaldehyde and isonicotinohydrazide. The vanillin group makes dihedral angles of 27.88 (7) and 58.94 (6)° with the planes of the pyridine and phenyl rings, respectively. A weak intermolecular C—HN hydrogen bond helps to consolidate the crystal packing.
organic compounds
The molecule of the title compound, C14H13N3O3, is non-planar. The isovanillin group is almost perpendicular to the pyridine ring, the dihedral angle being 85.26 (7)°. An intermolecular N—HO hydrogen bond and a bifurcated intra/intermolecular O—HO,N hydrogen-bond system help to establish the molecular conformation and consolidate the crystal packing.
organic compounds
The title compound, C20H16N4O5, is non-planar. The central benzene ring makes dihedral angles of 58.14 (6) and 5.00 (9)° with the terminal phenyl ring and the nitrophenylhydrazine mean plane, respectively. A bifurcated intra/intermolecular N—H(O,O) hydrogen bond helps to establish the molecular conformation and consolidate the crystal packing.
organic compounds
The molecule of the title compound, C20H18N4O6·C3H3N, is non-planar. The central benzene ring makes dihedral angles of 85.73 (10) and 2.70 (12)° with the terminal phenyl ring and the nitrophenylhydrazine mean plane, respectively. An intramolecular N—HO hydrogen bond helps to establish the molecular conformation.
organic compounds
The title compound, C27H27N3O3, was prepared by the reaction of 4-(benzyloxy)-3-ethoxybenzaldehyde and 4-amino-1,5-dimethyl-2-phenyl-1H-pyrazol-3(2H)-one. The ethylvanillin group makes dihedral angles of 72.97 (8) and 76.75 (5)° with the planes of the two terminal phenyl rings, and an angle of 39.24 (5)° with the pyrazolone ring plane. Intermolecular C—HN and C—HO hydrogen bonds help to consolidate the crystal packing.
organic compounds
The molecule of the title compound, C17H19N3O4, is not planar. The isovanillin group makes a dihedral angle of 3.23 (14)° with the phenylhydrazine residue. The nitro group and its attached aromatic ring are not coplanar, the dihedral angle between them being 3.18 (6)°. Intermolecular N—HO and C—HO hydrogen bonds link adjacent molecules, forming infinite chains.