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In the title compound, C12H11NO4, the dihedral angle between the benzene and isoxazole rings is 42.52 (8)°. The carb­oxy­lic acid group is close to being coplanar with the isoxazole ring [dihedral angle = 5.3 (2)°]. In the crystal, inversion dimers linked by pairs of O—H...O hydrogen bonds generate R22(8) loops.

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In the title mol­ecule, C20H17Cl2NO2, the pyrrole moiety makes dihedral angles of 63.42 (11) and 70.43 (12)° with the chlorobenzene rings. The eth­oxy­carbonyl unit is present in a synperiplanar conformation with respect to the pyrrole ring, as indicated by the dihedral angle of 14.5 (3)°. In the crystal, mol­ecules are linked into chains parallel to the a-axis direction by weak C—H...O hydrogen bonds.

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The asymmetric unit of the title compound C25H19N5OS, contains two mol­ecules, A and B. In mol­ecule A, the dihedral angles between the pyrazole ring and the C-bound phenyl group, the N-bound phenyl group and the thia­diazole ring are 32.30 (14), 52.25 (14) and 34.94 (12)°, respectively. The corresponding angles in mol­ecule B are 33.32 (14), 50.67 (15), and 70.30 (12)°, respectively. In the crystal, the A and B mol­ecules are linked by pairs of N—H...N hydrogen bonds, generating R22(8) loops. This dimer linkage is reinforced by two C—H...O hydrogen bonds and one C—H...N hydrogen bond.
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