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In the title compound, [Cu(C11H11BrNO)2], the CuII atom is in a distorted square-planar geometry, with the two bidentate ketimine ligands positioned in a trans geometry. Two inter­molecular C—H...O hydrogen bond inter­actions are present which link the mol­ecules in a zigzag manner along the a axis. The mol­ecules pack in layers along the diagonal of the bc plane.

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In the title compound, C11H12ClNO, intra­molecular N—H...O hydrogen bonding is present. The dihedral angle between the benzene ring and the pentenone unit is 46.52 (5)°. In the crystal, C—H...O inter­actions between hydrogen atoms of the aryl moiety and two separate oxygen atoms occur, leading to a three-dimensional network.

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The title compound, C10H15NO2, crystallized with three mol­ecules in the asymmetric unit. These three mol­ecules are quite similar except for slight differences in the torsion angles of the substituents on the ring. The isopropyl C—C—N—C torsion angles (towards the carbon next to the ethyl bound carbon), for example, are −150.63 (11), −126.77 (13) and −138.76 (11)° for mol­ecules A, B and C, respectively, and the C—C—C—N torsion angles involving the ethyl C atoms are 102.90 (13), 87.81 (14) and 86.47 (13)°. The main difference between the three mol­ecules lies in the way they are arranged in the solid-state structure. All three mol­ecules form dimers that are connected through strong O—H...O hydrogen bonds with R22(10) graph-set motifs. The symmetry of the dimers formed does however differ between mol­ecules. Mol­ecules B connect with each other to form inversion dimers. Mol­ecules A and C, on the other hand, form dimers with local twofold symmetry, but the two mol­ecules are crystallographically distinct. The B and C molecules are linked to themselves and to each other via C—H...O hydrogen bonds. This results in the formation of a three-dimensional network structure.
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