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organic compounds
The title compound, C14H12N4O6·C3H7NO, was prepared by the reaction of 2-hydroxy-3-methoxybenzaldehyde and 2,4-dinitrophenylhydrazine in N,N-dimethylformamide. In the crystal structure, the molecule of 2-hydroxy-3-methoxybenzaldehyde-2,4-dinitrophenylhydrazone is approximately planar, with a mean deviation of non-H atoms from the plane of 0.109 Å. The crystal packing is stabilized by O—H
O and N—HO hydrogen bonds and aromatic packing interactions.
O and N—HO hydrogen bonds and aromatic packing interactions.organic compounds
The title compound, C14H9F3N4O5S, was prepared from 4,4,4-trifluoro-1-(2-thienyl)butane-1,3-dione and 2,4-dinitrophenylhydrazine. The crystal structure shows that strong intramolecular hydrogen bonding determines the conformation of the individual molecules, while intermolecular hydrogen bonding and aromatic π-stacking interactions stabilize the structure in the solid state.
organic compounds
The title compound, C14H13N3O3, was prepared using 2-hydroxy-3-methoxybenzaldehyde and 4-pyridinecarboxylic acid hydrazide. In the crystal structure, an intramolecular O—HN hydrogen bond [HN = 1.83 (2) Å] appears to stabilize the planar conformation of the molecule, while intermolecular N—HN hydrogen bonds [HN = 2.213 (15) Å] link molecules into extended chains along [001].
N hydrogen bond [HN = 1.83 (2) Å] appears to stabilize the planar conformation of the molecule, while intermolecular N—HN hydrogen bonds [HN = 2.213 (15) Å] link molecules into extended chains along [001]. organic compounds
The title compound, C19H19N3O3, was prepared from 4-hydroxy-3-methoxybenzaldehyde and 4-amino-1,5-dimethyl-2-phenylpyrazolidin-3-one. The crystal structure shows that the molecules associate via intermolecular hydrogen bonds to form a supramolecular structure with a zigzag pattern.
organic compounds
The title compound, C13H11N3O2, was prepared by the reaction of pyridine-4-carboxylic acid hydrazide and p-hydroxybenzaldehyde in ethanol. In the crystal structure, all non-H atoms are coplanar, with an r.m.s. deviation of 0.096 Å. N—HN, O—HN and O—HO intermolecular hydrogen bonds stabilize the structure.
N, O—HN and O—HO intermolecular hydrogen bonds stabilize the structure.organic compounds
The title compound, C14H13N3O2·H2O, was prepared from pyridine-4-carboxylic acid hydrazide and 4-methoxybenzaldehyde. In the crystal structure, the water molecules participate in O—HO, O—HN and N—HO hydrogen bonds with the hydrazide molecules; these interactions contribute to the stability of the structure.
O, O—HN and N—HO hydrogen bonds with the hydrazide molecules; these interactions contribute to the stability of the structure.organic compounds
The title compound, C19H19N3O3, was prepared by the reaction of 2-hydroxy-3-methoxybenzaldehyde (o-vanillin) and 4-amino-1,5-dimethyl-2-phenylpyrazol-3-one. The crystal structure shows that a strong intramolecular O—HN hydrogen bond stabilizes the conformation of the molecule, while intermolecular C—HO hydrogen bonds give rise to a stable structure in the solid state.
N hydrogen bond stabilizes the conformation of the molecule, while intermolecular C—HO hydrogen bonds give rise to a stable structure in the solid state.organic compounds
The title compound [alternative name: pyridine-2-carbaldehyde 2,4-dinitrophenylhydrazone], C12H9N5O4, was prepared using pyridine-2-carbaldehyde and N-(2,4-dinitrophenyl)hydrazine. In the crystal structure, weak intermolecular C—HO hydrogen-bonding interactions link adjacent molecules to form a three-dimensional supramolecular network.
O hydrogen-bonding interactions link adjacent molecules to form a three-dimensional supramolecular network.organic compounds
The crystal structure of the title compound, C18H15Cl2N3O, shows that the Cl atoms take part in intermolecular C—HCl interactions.
Cl interactions.organic compounds
The components of the title solvate structure, C14H12N2O2·C3H7NO, are connected via N—HO, O—HN and O—HO hydrogen bonds, leading to a chain motif.
O, O—HN and O—HO hydrogen bonds, leading to a chain motif.organic compounds
The title compound, C17H18N2O4·H2O, was prepared by the reaction of 4-(2-hydroxyethoxy)-3-methoxybenzaldehyde and benzohydrazide. The crystal structure determination was undertaken in order to study the effect of intramolecular hydrogen bonding (C—HO and N—HO) on the molecular conformation, and the effect of intermolecular hydrogen bonding (O—HO, O—HN and C—HO) on the stability of the structure in the solid state.
O and N—HO) on the molecular conformation, and the effect of intermolecular hydrogen bonding (O—HO, O—HN and C—HO) on the stability of the structure in the solid state.organic compounds
The title compound, C18H17N3O2, was prepared using 3-hydroxybenzaldehyde and 4-amino-1,5-dimethyl-2-phenylpyrazolidin-3-one. The crystal structure of the title compound shows that intermolecular O—HO hydrogen-bonding interactions link adjacent molecules and contribute to the stability of the structure in the solid state.
O hydrogen-bonding interactions link adjacent molecules and contribute to the stability of the structure in the solid state.organic compounds
The title compound, C18H19N3O3, was prepared using 4-hydroxybenzaldehyde and 4-amino-1,5-dimethyl-2-phenylpyrazolidin-3-one. The crystal structure shows that the title compound includes a water molecule, which forms O—HO hydrogen bonds with adjacent molecules and plays an important role in the stabilization of the crystal structure.
O hydrogen bonds with adjacent molecules and plays an important role in the stabilization of the crystal structure.organic compounds
The title compound, C14H12BrNO2, was prepared from 2-hydroxy-3-methoxybenzaldehyde and 4-bromophenylamine. The 4-hydroxy-3-methoxyphenyl and bromobenzene groups are trans with respect to the imino bond. The planarity of the molecule is supported by the conjugation of the imino group and the aromatic system, together with a resonance-assisted intramolecular hydrogen bond [O—HN = 2.610 (3) Å].
N = 2.610 (3) Å].organic compounds
The title compound, C22H26O6, was prepared by the reaction of 4-hydroxy-3-methoxybenzaldehyde and 1,6-dibromohexane, displays molecular symmetry Ci, and has a crystallographic centre of inversion located at the mid-point of the C-C bond of the aliphatic chain. The zigzag aliphatic chain is coplanar with the aromatic rings of the vanillin groups.
organic compounds
The title compound, C18H18O6, was prepared by the reaction of 4-hydroxy-3-methoxybenzaldehyde and 1,2-dibromoethane. There are one and a half molecules in the asymmetric unit; one has C1 molecular symmetry and the other Ci, with the centre of inversion at the mid-point of the aliphatic C-C bond. The ethylenedioxy groups are coplanar with the aromatic systems of the vanillin groups.
organic compounds
The title compound, C20H22O6, comprises two o-vanillin subunits covalently linked to a central butyl chain; the molecule lies on an inversion center. The dihedral angle between the bridging butyl group and the plane through the aromatic ring is 7.13 (14)°, indicating the overall planarity of the molecule. The molecules are linked by weak C—HO hydrogen bonds.
O hydrogen bonds.organic compounds
The molecule of the title compound, C21H17N5O8, is non-planar. The central benzene ring makes dihedral angles of 39.57 (10) and 2.93 (17)° with the two terminal benzene rings. An intramolecular N—HO hydrogen bond helps to establish the molecular conformation.
O hydrogen bond helps to establish the molecular conformation.organic compounds
The asymmetric unit of the title compound, C14H10Cl2N2O, comprises two independent molecules, in which the dihedral angles between the terminal phenyl and substituted benzene rings are 21.28 (10) and 39.60 (12)°. N—HO, C—HO and C—HCl hydrogen bonds stabilize the conformations of the molecules and also stabilize the structure in the solid state.
O, C—HO and C—HCl hydrogen bonds stabilize the conformations of the molecules and also stabilize the structure in the solid state.
