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The heterocyclic ring in the title compound, C13H17BrO, adopts a 1C4 conformation, with the phenyl and bromo substituents located in equatorial positions.

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The tetra­hydro­pyran ring in the title compound, C13H18O2, adopts a 1C4 conformation, with the phenyl and the hydroxy substituent located in equatorial positions. Hydro­gen bonding occurs between enantiomers involving the hydroxy H atom and the ether O atom.

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The title compound, C13H14O4, crystallizes as a racemate. The heterocyclic core of the 3S-configured mol­ecule adopts a 2T3 conformation, whereas a 2T3 arrangement is found for the 3R enantiomer. The majority of substituents in both stereoisomers are located in axial positions.

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The title compound, C19H21Cl, exhibits a symmetrically arranged 1,3-diphenyl-2,2-dimethyl­propyl entity, with a 1-chloro and a 3-vinyl substituent displaced on opposite sides of the plane defined by the three C atoms that bridge the two aromatic subunits.

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The p-cresyl substituent is inclined by -69.5 (10)° and the heterocyclic subunit is tilted by 88.4 (7)° with respect to the bridging carbonate functionality in the title compound, C12H11NO3S2.

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The neutral complex trans-[VOCl2(H2O)2] co-crystallizes with di-2-pyridylamine hydro­chloride to provide the title compound, (C10H10N3)2[VCl2O(H2O)2]Cl2. The V-bound aqua ligands form two hydrogen bonds each. The amine functionality of the 2-(2-pyridylamino)pyridinium cation participates as a monovalent donor in the hydrogen bonding. In both instances, inter­stitial Cl- ions serve as hydrogen-bond acceptors. The three hydrogen bonds that are formed per anion give rise to one-dimensional chains along [100].

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In the title compound, C10H5Cl4NS2, the CCl3 group is displaced by 78.4 (4)° from the thia­zole plane. The torsion angle between the heterocyclic core and the 4-chloro­phenyl substituent is -7.0 (6)°.

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A Z arrangement of substituents about the carboxyl­ate C-O bond causes a syn positioning of the carbonyl O atom and the heterocyclic part of the title compound, C18H15NO3S. The carboxyl­ate entity is inclined by -28.1 (3)° to the phenyl group. The planes of the thia­zol-2(3H)-thione subunit and the carboxyl­ate group are orthogonally arranged.

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The geometry of the title compound, C5H7NOS2·0.5H2O, is characterized by a planar N,S-heterocyclic core that is distorted from a regular penta­gon. Solvent water participates in non-chelated hydrogen bonds and acts as a twofold donor (O—H...S=C) and a twofold acceptor [O...H—O(—N)].

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The mol­ecules of the title compound, C11H11NOS2, form hydrogen-bonded dimers in the solid state. The amide H atom serves as hydrogen-bond donor and the thio­carbonyl S atom of a neighbouring mol­ecule serves as acceptor. The p-methoxy­phenyl substituent is tilted by 7.3 (5)° from the thia­zole-2(3H)-thione plane.

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In the title compound, C11H14O2, the tetra­hydro­pyran ring adopts a 1C4 conformation, with the phen­yl and the hydr­oxy substituents located in equatorial positions. Hydrogen bonding occurs in the solid state between hydr­oxy groups to link two mol­ecules of (R,R)-trans-4-phen­ylperhydro­pyran-3-ol and two mol­ecules of the (S,S)-enantiomer to provide tetra­mers.

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The title compound, C12H12O2S2, is a chiral O,S-dialkyl dithio­carbonate. The O-ethyl substituent and the dithio­carbonate functionality form a plane, which is twisted by 60.7 (2)° from the S-(3-oxoindan-1-yl) group.

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The title compound, C14H18BrFO, is a hexa­substituted tetra­hydro­pyran with two halogen atoms attached in β and four C substituents in α positions with respect to the ether O atom. The C...C distance [3.183 (7) Å] between the two 1,3-diaxially oriented α-methyl groups falls below the sum of the van der Waals radii. The magnitude of the bond angle at oxygen [122.6 (3)°] and a comparatively small displacement of this atom [0.490 (5) Å] from the mean plane of four C atoms of the tetrahydropyran ring indicate a marked flattening of the heterocyclic ring in its 1C4 conformation.

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The stereogenic centre in the title compound, C14H19NO4S2, is substituted with a dithio­carbonate, an ethyl­oximino and a 3,4-dimethoxy­phenyl group, as well as an H atom. Tandem hydrogen-bonding occurs between enantiomers to produce dimers, in which the oxime H atom serves as donor toward the oxime N atom of an adjacent mol­ecule.

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In the title compound, C18H10Cl2N2S4, a 1,2-substituted disulfane, the torsion angle between the p-chloro­phenyl and the 1,3-thia­zole rings is -2.0 (6)° for the group attached to the the first disulfane S atom, and 14.6 (7)° for the substitutent located at the second.

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The asymmetric unit of the title compound, C18H10Cl2N2S4, consists of one full mol­ecule and two half mol­ecules, which are completed by twofold rotation symmetry.
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