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addenda and errata
organic compounds
The molecule of the title compound, C15H13O2N3, deviates slightly from planarity. There is a strong intramolecular N
O hydrogen bond of 2.5831 (19) Å. The molecule exists in the phenol–imine form and the dihedral angle between the two aromatic ring systems is 14.61 (5)°.
O hydrogen bond of 2.5831 (19) Å. The molecule exists in the phenol–imine form and the dihedral angle between the two aromatic ring systems is 14.61 (5)°.organic compounds
The title compound, C13H11NO3, adopts the keto–amine tautomeric form, with the H atom located on N rather than on O. This H atom is involved in a strong intramolecular hydrogen bond. There are two independent molecules in the asymmetric unit. The molecules are linked by intramolecular N—HO and O—HO and intermolecular O—HO hydrogen bonds into a three-dimensional network.
O and O—HO and intermolecular O—HO hydrogen bonds into a three-dimensional network.organic compounds
The title compound, C15H12NO2F3, adopts the phenol–imine tautomeric form. The two aromatic rings are twisted with respect to each other, with a dihedral angle of 17.83 (19)°. O—HN and O—HF intramolecular interactions are found in the molecule, and the solid-state structure is stabilized by intermolecular C—HO and C—HF hydrogen bonds, to form a two-dimensional network.
N and O—HF intramolecular interactions are found in the molecule, and the solid-state structure is stabilized by intermolecular C—HO and C—HF hydrogen bonds, to form a two-dimensional network.organic compounds
The molecule of the title compound, C14H13NO3, adopts the keto–amine tautomeric form. An intramolecular N—HO hydrogen bond dictates the essentially planar molecular geometry; the two benzene rings make a dihedral angle of 7.93 (7)°. The crystal packing is stabilized by intermolecular O—HO and C—HO hydrogen bonds.
O hydrogen bond dictates the essentially planar molecular geometry; the two benzene rings make a dihedral angle of 7.93 (7)°. The crystal packing is stabilized by intermolecular O—HO and C—HO hydrogen bonds.organic compounds
The title compound, C19H23N3O4, adopts the keto-amine tautomeric form, with the H atom located on N rather than on O. This H atom is involved in a strong intramolecular hydrogen bond. The configuration around the azo N=N double bond is trans and the dihedral angle between the two aromatic rings is 8.94 (2)°. The molecules, with intramolecular N—HO hydrogen bonding, are linked by intermolecular O—HO hydrogen bonds, forming a three-dimensional network.
O hydrogen bonding, are linked by intermolecular O—HO hydrogen bonds, forming a three-dimensional network.organic compounds
The title compound, C14H12N2O4, exists as an enol–imine tautomer, in which a strong intramolecular O—HN hydrogen bond is formed. This study verifies the preference of the enol–imine tautomeric form in the solid state.
N hydrogen bond is formed. This study verifies the preference of the enol–imine tautomeric form in the solid state.organic compounds
The title compound, C15H14N2O4, exists as an enol–imine tautomer, in which a strong intramolecular O—HN hydrogen bond is formed. This work verifies the preference for the enol–imine tautomeric form in the solid state.
N hydrogen bond is formed. This work verifies the preference for the enol–imine tautomeric form in the solid state.organic compounds
The title compound, C22H30ClO4PS, displays distorted tetrahedral geometry around the P atom. The dihedral angle between the benzene rings is 41.2 (2)°. Because of the steric effects of the tert-butyl groups, the aromatic rings have unusual endocyclic angles. The molecules are linked by weak C—Hπ interactions.
π interactions.organic compounds
The title compound, C14H13N1O3, adopts the keto–amine tautomeric form, with an intramolecular N—HO resonance-assisted hydrogen bond. The two benzene rings are nearly coplanar [dihedral angle = 14.3 (2)°]. The molecules are linked by intermolecular O—HO hydrogen bonds and C—H π interactions between methyl groups and benzene rings.
O resonance-assisted hydrogen bond. The two benzene rings are nearly coplanar [dihedral angle = 14.3 (2)°]. The molecules are linked by intermolecular O—HO hydrogen bonds and C—H π interactions between methyl groups and benzene rings.organic compounds
In the title structure, C14H11N2O2Cl, the benzene rings are in a trans configuration with respect to the azo double bond and the molecule is essentially planar.
organic compounds
The molecule of the title compound, C17H13NO2, is nearly planar and exists in the keto–amine (N—HO) tautomeric form, with a strong intramolecular hydrogen bond of 2.576 (2) Å between the O and N atoms. The molecules are linked by O—HO hydrogen bonds to form dimers, and are further linked by C—Hπ interactions, forming a three-dimensional network.
O) tautomeric form, with a strong intramolecular hydrogen bond of 2.576 (2) Å between the O and N atoms. The molecules are linked by O—HO hydrogen bonds to form dimers, and are further linked by C—Hπ interactions, forming a three-dimensional network.organic compounds
In the title structure, C16H16N2O3, the benzene rings are in a trans configuration with respect to the azo double bond and the molecule is essentially planar.
organic compounds
The title compound, C22H16N4O, displays a trans configuration with respect to the –N=N– double bond, as found for other diazene derivatives. There is a weak intramolecular C—HN hydrogen bond, which seems to have an effect on the molecular conformation. The crystal packing is governed by weak intermolecular C—HN and C—HO hydrogen bonds, and weak C—Hπ stacking.
N hydrogen bond, which seems to have an effect on the molecular conformation. The crystal packing is governed by weak intermolecular C—HN and C—HO hydrogen bonds, and weak C—Hπ stacking.organic compounds
The title compound, C20H25N3O5, adopts the keto–amine tautomeric form and displays the characteristic features of azobenzene derivatives. Intramolecular N—HO and O—HO and intermolecular O—HO interactions influence the conformation of the molecules and the crystal packing.
O and O—HO and intermolecular O—HO interactions influence the conformation of the molecules and the crystal packing.organic compounds
The title compound, C13H18N2O2, exists in the enol–imine tautomeric form with a strong intramolecular O—HN hydrogen bond [ON = 2.5795 (18) Å], and the morpholine ring adopts an almost perfect chair conformation.
N hydrogen bond [ON = 2.5795 (18) Å], and the morpholine ring adopts an almost perfect chair conformation.organic compounds
The molecule of the title compound, C19H20F3N3O5, at 150 K, is nearly planar and exists in the keto–amine (N—HO) tautomeric form, with a strong intramolecular hydrogen bond of 2.585 (2) Å between the O and N atoms. The configuration around the azo –N=N– double bond is trans, as found for other diazene derivatives, and the dihedral angle between the planes of the two aromatic rings is 7.81 (4)°.
O) tautomeric form, with a strong intramolecular hydrogen bond of 2.585 (2) Å between the O and N atoms. The configuration around the azo –N=N– double bond is trans, as found for other diazene derivatives, and the dihedral angle between the planes of the two aromatic rings is 7.81 (4)°.organic compounds
The title compound, C22H29N3O5, is approximately planar with the aromatic rings in a trans configuration with respect to the azo double bond. The eneamine portion of the molecule exists as the keto–amine tautomer, stabilized by a strong intramolecular N—HO hydrogen bond. Intramolecular N—HO and O—HO and intermolecular O—HO and C—HO interactions influence the conformation of the molecules and the crystal packing.
O hydrogen bond. Intramolecular N—HO and O—HO and intermolecular O—HO and C—HO interactions influence the conformation of the molecules and the crystal packing.organic compounds
The molecule of the title compound, C13H9ClN2O2, is approximately planar and displays a trans configuration with respect to the central N=N double bond. The dihedral angle between the two aromatic rings is 3.69 (14)°. The molecules are linked by intermolecular O—HO hydrogen bonds, forming a two-dimensional network.
O hydrogen bonds, forming a two-dimensional network.organic compounds
The molecule of the title compound, C13H9BrN2O2, is approximately planar and displays a trans configuration with respect to the N=N double bond. The dihedral angle between the two aromatic rings is 3.65 (16)°. The molecules are linked by intermolecular O—HO hydrogen bonds, forming a two-dimensional network.
O hydrogen bonds, forming a two-dimensional network.organic compounds
The molecule of the title compound, C15H14N2O2, is approximately planar and displays a trans configuration with respect to the N=N double bond. The dihedral angle between the two aromatic rings is 10.90 (14)°. The molecules are stacked via weak C—Hπ interactions.
π interactions.organic compounds
The title structure, C14H11BrN2O3, displays the characteristic features of azobenzene derivatives. The two aromatic rings are nearly coplanar, forming a dihedral angle of 8.71 (12)°. There is a strong intramolecular O—HO bond, and weak π–π and C—Hπ interactions stabilize the structure.
O bond, and weak π–π and C—Hπ interactions stabilize the structure.organic compounds
The title compound, C14H11FN2O3, displays the characteristic features of azobenzene derivatives. Intramolecular O—HO and weak π–π interactions influence the conformation of the molecules and the crystal packing. The azobenzene moiety of the molecule has a trans configuration and the dihedral angle between the planes of the two aromatic rings is 10.13 (8)°.
O and weak π–π interactions influence the conformation of the molecules and the crystal packing. The azobenzene moiety of the molecule has a trans configuration and the dihedral angle between the planes of the two aromatic rings is 10.13 (8)°.
