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The complete molecule of the compound, C6H4N8O3, is generated by a crystallographic twofold rotation axis that runs through the central ring. The flanking ring is twisted by 20.2 (1)° with respect to the central ring. One of the amino H atoms forms an intra­molecular N—H...N hydrogen bond; adjacent mol­ecules are linked by N—H...N hydrogen bonds forming a chain running along [10-2].

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In the title compound, C6H10N6O4, the nitro­amine –NHNO2 substituent and the C–N=N(→ O) unit of the other substituent of the oxadiazole ring are nearly coplanar with the five-membered ring [dihedral angles = 5.7 (1) and 3.0 (1)°]. The amino group of the –NHNO2 substituent is a hydrogen-bond donor to the two-coordinate N atom of the C—N=N(→ O) unit.
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